general topology - A metric space is compact iff it is pseudocompact - Mathematics Stack Exchange
Analysis WebNotes: Chapter 06, Class 31
general topology - Show $A$ is compact subset of a metric space $(X,\mathscr T, d)$ only if for all $x \in X$, $d(x,A)=d(x,a)$ for some $a \in A$. - Mathematics Stack Exchange
Show that in any metric space, a compact set is bounded. Solution.pdf
Fundamentals of Topologies & Metric Spaces – deep mind
SOLVED: Let (S,d) be a compact metric space (not necessarily in R 0 Rk and let Fi 2 F2 2 F3 2 be a non-increasing sequence of nonempty closed sets Fn Show
Topology: Sequentially Compact Spaces and Compact Spaces | Mathematics and Such
SOLVED: Compactness Chapter 3-6: Connectedness 5 172 subset of R is compact in the topology Jf. (See Show that every Example € of R in the topology 6, Is [0, 1] compact
general topology - Help understanding why a complete, totally bounded metric space implies every infinite subset has a limit point - Mathematics Stack Exchange
calculus - Question about the proof of "If K is a compact set of the metric space Ω, then K is closed" - Mathematics Stack Exchange
Solved 3. Use the definition of compactness to prove that | Chegg.com
Topology: One-Point Compactification and Locally Compact Spaces | Mathematics and Such
Closedness of Compact Sets in a Metric Space - Mathonline